Skip to main content

no-unsafe-return

Disallow returning a value with type any from a function.

Despite your best intentions, the any type can sometimes leak into your codebase. Returned any typed values are not checked at all by TypeScript, so it creates a potential safety hole, and source of bugs in your codebase.

Attributes

  • Included in configs
    • ✅ Recommended
    • 🔒 Strict
  • Fixable
    • 🔧 Automated Fixer
    • 🛠 Suggestion Fixer
  • 💭 Requires type information

Rule Details​

This rule disallows returning any or any[] from a function. This rule also compares the return type to the function's declared/inferred return type to ensure you don't return an unsafe any in a generic position to a receiver that's expecting a specific type. For example, it will error if you return Set<any> from a function declared as returning Set<string>.

Examples of code for this rule:

function foo1() {
  return 1 as any;
}
function foo2() {
  return Object.create(null);
}
const foo3 = () => {
  return 1 as any;
};
const foo4 = () => Object.create(null);

function foo5() {
  return [] as any[];
}
function foo6() {
  return [] as Array<any>;
}
function foo7() {
  return [] as readonly any[];
}
function foo8() {
  return [] as Readonly<any[]>;
}
const foo9 = () => {
  return [] as any[];
};
const foo10 = () => [] as any[];

const foo11 = (): string[] => [1, 2, 3] as any[];

// generic position examples
function assignability1(): Set<string> {
  return new Set<any>([1]);
}
type TAssign = () => Set<string>;
const assignability2: TAssign = () => new Set<any>([true]);

There are cases where the rule allows to return any to unknown.

Examples of any to unknown return that are allowed.

function foo1(): unknown {
  return JSON.parse(singleObjString); // Return type for JSON.parse is any.
}

function foo2(): unknown[] {
  return [] as any[];
}

Options​

// .eslintrc.json
{
  "rules": {
    "@typescript-eslint/no-unsafe-return": "error"
  }
}

This rule is not configurable.